(x+7)(5x-1)=29x+3x^2

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Solution for (x+7)(5x-1)=29x+3x^2 equation:


Simplifying
(x + 7)(5x + -1) = 29x + 3x2

Reorder the terms:
(7 + x)(5x + -1) = 29x + 3x2

Reorder the terms:
(7 + x)(-1 + 5x) = 29x + 3x2

Multiply (7 + x) * (-1 + 5x)
(7(-1 + 5x) + x(-1 + 5x)) = 29x + 3x2
((-1 * 7 + 5x * 7) + x(-1 + 5x)) = 29x + 3x2
((-7 + 35x) + x(-1 + 5x)) = 29x + 3x2
(-7 + 35x + (-1 * x + 5x * x)) = 29x + 3x2
(-7 + 35x + (-1x + 5x2)) = 29x + 3x2

Combine like terms: 35x + -1x = 34x
(-7 + 34x + 5x2) = 29x + 3x2

Solving
-7 + 34x + 5x2 = 29x + 3x2

Solving for variable 'x'.

Reorder the terms:
-7 + 34x + -29x + 5x2 + -3x2 = 29x + 3x2 + -29x + -3x2

Combine like terms: 34x + -29x = 5x
-7 + 5x + 5x2 + -3x2 = 29x + 3x2 + -29x + -3x2

Combine like terms: 5x2 + -3x2 = 2x2
-7 + 5x + 2x2 = 29x + 3x2 + -29x + -3x2

Reorder the terms:
-7 + 5x + 2x2 = 29x + -29x + 3x2 + -3x2

Combine like terms: 29x + -29x = 0
-7 + 5x + 2x2 = 0 + 3x2 + -3x2
-7 + 5x + 2x2 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
-7 + 5x + 2x2 = 0

Factor a trinomial.
(-7 + -2x)(1 + -1x) = 0

Subproblem 1

Set the factor '(-7 + -2x)' equal to zero and attempt to solve: Simplifying -7 + -2x = 0 Solving -7 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -2x = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -2x = 0 + 7 -2x = 0 + 7 Combine like terms: 0 + 7 = 7 -2x = 7 Divide each side by '-2'. x = -3.5 Simplifying x = -3.5

Subproblem 2

Set the factor '(1 + -1x)' equal to zero and attempt to solve: Simplifying 1 + -1x = 0 Solving 1 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1x = 0 + -1 -1x = 0 + -1 Combine like terms: 0 + -1 = -1 -1x = -1 Divide each side by '-1'. x = 1 Simplifying x = 1

Solution

x = {-3.5, 1}

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